Page 247 - DCOM303_DMGT504_OPERATION_RESEARCH
P. 247

Operations Research




                    Notes          Solution:
                                   1.  From the data given in the problem, the activity network is constructed as shown  in
                                       Figure 5.6.

                                                         Figure  12.15:  Activity  Network  Diagram

                                                            1              5
                                                   2               4                9
                                                                                                7
                                                 4
                                                                                                         10
                                                                                                   5
                                                        1                     7      2
                                        1                                                     8
                                                                         8
                                                                                         1
                                                 1         6                   4
                                                   3               5
                                                                                     6


                                   2.  To determine the critical path, compute the earliest, time T  and latest time T  for each of
                                                                                       E             L
                                       the activity of the project. The calculations of T  and T are as follows:
                                                                             E     L
                                       To calculate T  for all activities,
                                                   E
                                       T     = 0
                                         E1
                                       T     = T  + t  = 0 + 4 = 4
                                         E2    E1  1, 2
                                       T     = T  + t  = 0 + 1 =1
                                         E3    E1  1, 3
                                       T     = max (T  + t  and T  + t )
                                         E4         E2  2, 4   E3  3, 4
                                             = max (4 + 1 and 1 + 1) = max (5, 2)

                                             = 5 days
                                       T     = T  + t  = 1 + 6 = 7
                                         E5    E3  3, 6
                                       T     = T  + t  = 7 + 4 = 11
                                         E6    E5  5, 6
                                       T     = T  + t  = 7 + 8 = 15
                                         E7    E5  5, 7
                                       T     = max (T  + t  and T  + t )
                                         E8         E6  6, 8   E7  7, 8
                                             = max (11 + 1 and 15 + 2) = max (12, 17)
                                             = 17 days
                                       T     = T  +t  = 5 + 5 = 10
                                         E9    E4    4, 9
                                       T     = max (T  + t  and T  + t  )
                                         E10        E9  9, 10   E8  8, 10
                                             = max (10 + 7 and 17 + 5) = max (17, 22)

                                             = 22 days










          242                               LOVELY PROFESSIONAL UNIVERSITY
   242   243   244   245   246   247   248   249   250   251   252