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Unit 8: Derivatives




                    The variables are:                                                          Notes
                       S = Stock price
                       X = Strike price
                       t = Time remaining until expiration, expressed as a percent of a year
                       r = Current continuously compounded risk-free interest rate
                       v = Annual volatility of stock price (the standard deviation of the short-term
                          returns over one year). See below for how to estimate volatility.
                      ln = Natural logarithm
                    N(x) = Standard normal cumulative distribution function
                       e = Exponential function
                    or
                    The Black-Scholes model for valuing a European call is:
                       C = SN(d ) – Xe –r(T–t)  N(d )
                              1           2
                    Where,
                           ln(S/X) (r  2  /2(T  t)
                      D =
                       1            T  t

                      D = d      T  t
                       2    1
                       C = Call option premium
                       S = Current asset price
                       X = Exercise price
                      T-t = Time to expiry in decimals of a year
                         = The annualized standard deviation of  the natural log of  the asset price
                          relative in decimals
                      ln = Natural logarithm
                    N(d ) = Cumulative standard normal probability distribution
                       1
                 d  and d = Standardised normal variables
                  1    2
                       r = Risk-free rate on interest in decimals (continuously compounded)


                 Example: The current asset price is 35.0, the exercise price is 35.0, the risk-free rate of
          interest is 10%, the volatility is 20% and the time to expiry is one year. Thus S = 35, X = 35, (T – t)
          = 1.0, r = 0.1 and   = 0.2.
          Solution:

          First, we calculate d , then d and, finally, the present value of the exercise price Xe  –r(T – t)
                          1      2
                                                              2
                                              ln(35/35) + (0.1 + 0.2 /2) × 1.0
                                         d =                           = 0.60
                                           1           0.2 1.0
                              d  – d  – 0.2 1.0 = 0.4
                               2  1
                                     Xe –r(T – t)  = 35e –(0.1 × 1.0)  = 31.66934




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