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Unit 4: Determinants




          The total cost of the two Production Departments, denoted by P  and P , is given by   Notes
                                                              1    2
                                                             39994.19
                          P      60000     0.40 0.35 0.25                106493.24
                           1                                 29995.64
                          P   =  74000     0.20 0.40 0.20                109994.77
                           2                                 79988.37
          Thus,             P  =   1,06,493.24 and P  =   1,09,994.77.
                             1                 2

                 Example

          An amount of   4,000 is distributed into three investments at the rate of 7%, 8% and 9% per
          annum respectively. The total annual income is   317.50 and the annual income from the first
          investment is   5 more than the income from the second. Find the amount of each investment.
          Solution:
          Let x , x and x  denote the amount of first, second and third investments respectively. We can
              1  2    3
          write
                                   x  + x  + x  = 4,000                           .... (1)
                                    1   2  3
          Also            0.07x  + 0.08x  + 0.09x  = 317.50
                              1      2     3
          or                     7x  + 8x  + 9x  = 31,750                         .... (2)
                                  1    2   3
          Further,               0.07x  – 0.08x  = 5
                                     1     2
          or                         7x  – 8x  = 500                              .... (3)
                                       1   2
          Writing the above equations in matrix form

                             1    1 1   x 1      4000
                             7    8 9   x    =  31750  or AX = D
                                         2
                             7    8 0   x         500
                                         3
          Here                          |A| = 23
                                                 4000   1 1
          Also                          |A | =  31750   8 9  = 34500,
                                          1
                                                  500   8 0

                                                1   4000 1
                                        |A | = 7 31750 9  = 28750
                                          2
                                               7     500 0
                                                1   1   4000
          and                           |A | = 7    8 31750  = 28750
                                          3
                                               7    8    500

                                               34500
                                          x  =        =   1,500
                                           1
                                                23
                                                   28750
          and                             x  = x 3        =   1,250.
                                           2
                                                     23




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