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Basic Mathematics – I




                    Notes
                                          Example
                                   To control a crop disease, it is necessary to use 8 units of chemical A, 14 units of chemical B and
                                   13 units of chemical C. One barrel of spray P contains 1 unit of A, 2 units of B and 3 units of C. One
                                   Barrel of spray Q contains 2 units of A, 3 units of B and 2 units of C. One barrel of spray R contains
                                   1 unit of A, 2 units of B and 2 units of C. Find how many barrels of each spray be used to just meet
                                   the requirement?
                                   Solution:
                                   Let x barrels of spray P, y barrels of spray Q and z barrels of Spray R be used to just meet the
                                   requirement.
                                   The above information can be written as the following matrix equation.
                                              x + 2y + z = 8
                                             2x + 3y + 2z = 14

                                             3x + 2y + 2z = 13

                                                          1 2 1             8
                                   Let              A =   2 3 2 and B      14
                                                          3 2 2            13

                                                  |A| = 6 + 12 + 4 – 9 – 4 – 8 = 1

                                                                  2    2   1
                                                   A  = Adj A     2    1   0
                                                     –1
                                                                   5   4    1


                                                   x      2    2   1   8     1
                                                   y  =   2    1   0   14    2
                                                   z       5   4    1 13     3

                                   i.e.              x = 1, y = 2, z = 3 barrels of spray P, Q and R respectively.


                                          Example
                                   An amount of   65,000 is invested in three investments at the rate of 6%, 8% and 9% per annum,
                                   respectively. The total annual income is   4,800. The income from the third investment is   600
                                   more than the income from second investment. Using matrix algebra, determine the amount of
                                   each investment.
                                   Solution:
                                   Let x, y and z be the amount invested in the three investments. Thus, we can write
                                                       x + y + z = 65000

                                              0.06x + 0.08y + 0.09z = 4800   or   6x + 8y + 9z = 4,80,000
                                                   –0.08y + 0.09z = 600  or  8y – 9z = –60,000






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