Page 12 - DMTH202_BASIC_MATHEMATICS_II
P. 12
Unit 1: Integration
Before starting, however, let us remind some helpful trigonometric identities. Notes
2
2
2
The first is the Pythagorean Identity: sin + cos = 1. If we divide all terms by cos , then we
have:
2
2
sin cos 1
2
2
tan 1 sec .
2
2
cos cos cos 2
The well-known trigonometric identities
a 2 a 2 sin 2 t a 2 cos 2 t 1
a 2 a 2 tan 2 t a 2 sec 2 t 2
a 2 sec 2 t a 2 tan 2 t 3
may be used to eradicate radicals from integrals. Particularly when these integrals entail a x 2
2
2
2
and x a .
1. For a x 2 set x a sin t . In this case we converse regarding sine-substitution.
2
2. For a x 2 set x a tan t . In this case we converse regarding tangent-substitution.
2
3. For x a set x a sec t . In this case we converse regarding secant-substitution.
2
2
2
2
2
2
The expressions a x and x a should be observed as a constant plus-minus a square of a
2
function. Here, x displays a function and a a constant. For example, x 2x 3 can be observed as
one of the two previous expressions. Certainly, if we complete the square we obtain
2
2
3
x 2x x 1 2
1
2
where a = 2. Thus from the above substitutions, we will set x 2 tan t .
The following examples exemplify how to apply trigonometric substitutions:
2
Example: Find x 3 4 x dx
Solution:
It is simple to observe that sine-substitution is the one to use. Set x 2sin t or equivalently
t sin 1 /2x . Then dx 2cos t dt which provides us
2
x 3 4 x dx 8sin 2 4 4sint 2 2 cost .t dt
Easy calculations provide
2
x 3 4 x dx 32 sin 2 cost 2 .t dt
Technique of integration of powers of trigonometric functions give
sin 3 cost 2 t dt 1 cos 2 cost 2 sint t dt
which recommends the substitution v cos t . Hence dv sin t dt which implies
v 3 v 5
2
2
2
2
1 cos cost sint t dt 1 v v dv . C
3 5
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