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Basic Mathematics – I




                    Notes         Then, using the chain rule,
                                                       dy
                                                 dy    dt              dx
                                                     =         provided     0
                                                 dx    dx              dt
                                                       dt

                                                 dy    2t  1
                                                     =
                                                 dx     3t  2
                                                                1 dy            1                            1
                                  From this we can see that when  t  ,  0 and so t   is a stationary value. When  t  ,
                                                                2 dx            2                            2

                                      1        1
                                   x    and y     and these are the coordinates of the stationary point.
                                      8        4
                                                          dy
                                  We also note that when t  0,   is infinite and so the y axis is tangent to the curve at the point (0, 0).
                                                          dx

                                  11.3 Second Derivatives


                                                                                        2
                                                                                       d y
                                          Example: Suppose we wish to find the second derivative    when
                                                                                       dx  2
                                                  x = t  2              y = t  3

                                  Differentiating we find
                                                 dx                   dy
                                                     = 2t                 = 3t 2
                                                 dt                    dt
                                  Then, using the chain rule,

                                                       dy
                                                 dy                   dx
                                                     =  dt    provided      0
                                                 dx    dx              dt
                                                       dt

                                  So that

                                                 dy    3t  2  3t
                                                     =
                                                 dx     2t  2

                                                                                                      2
                                                                                                     d y
                                  We can apply the chain rule a second time in order to find the second derivative,   .
                                                                                                     dx 2
                                                             2
                                                            d y    d  dy
                                                                =
                                                            dx  2  dx dx









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