Page 36 - DMTH201_Basic Mathematics-1

Unit 2: Trigonometric Functions-II

Notes
or

= (2p + 1) – or = 2 + …(1)

From (1), we get
n
= n + (–1) , n I as the general solution of the equation sin = sin

To find the general solution of the equation cos = cos
It is given that, cos = cos

cos – cos = 0

= 0

Either, or

or

= 2p – or = 2p + ....(1)

From (1), we have
= 2n ± ,n I as the general solution of the equation cos = cos

To find the general solution of the equation tan = tan
It is given that, tan = tan

= 0

sin cos – sin cos = 0
sin( – ) = 0

– = n , n I
= n + n I

Similarly, for cosec = cosec , the general solution is
n
= n + (–1)
and, for sec = sec , the general solution is
= 2n

and for cot = cot
= n + is its general solution

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