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Unit 5: Definite Integrals by Substitution




                                                                                               Notes
                             x
          (d)   2  cos  cos sinx      dx
                 
               This problem not as awful as it appears.  Here is the substitution and converted limits.
                                u   sin x    du   cos x dx

                                  
               x           u   sin    1    x         u   sin      0
                  2                2
               The cosine in the very front of the integrand will get substituted away in the differential
               and so this integrand in fact simplifies down considerably.  Here is the integral.
                                                    1
                                    2  cos  cos sinx     dx   0   cos u du
                                              x
                                                         1
                                                     sin   u
                                                         0

                                                     sin   1   sin    0
                                                     sin   1
               Don’t get energized about these types of answers.  On occasion we will finish up with trig
               function assessments like this.
                   2
                2 e  w
          (e)   1   dw
                50 w  2
               This is also a complicated substitution (at least until you see it).  Here it is,
                     2            2                      1       1
                  u         du    dw                   dw    du
                     w            w  2                   w  2    2
                                                    1
                  w   2            u   1     w                u  100
                                                   50
               Here is the integral.
                                           2
                                        2 e  w   1  1  u
                                        1   2  dw    100   e du
                                        50 w     2
                                                     1
                                                  1
                                                  e u
                                                  2  100
                                                1
                                                  1
                                                 e   e 100 
                                                2
                           2  x dx
              Task  Evaluate    1  2  3     by using substitution method.
                            x    2
          Self Assessment

          Fill in the blanks:

          6.   The first method  used to evaluate definite integral by substitution is to calculate  the
               indefinite integral, articulating an antiderivative in terms of the original variable, and
               then assess the consequence at the ............................... limits.
          7.   The second method used to evaluate definite integral by substitution is to ...............................
               the original limits to new limits in provisions of the new variable and do not translate the
               antiderivative back to the original variable.
          8.   Sometimes a ............................... will stay similar after the substitution.



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