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Simulation and Modelling



                      Notes         In Table 11.1 and Table  11.2 we  compare for  N = 10 and  F(x) = 1 –  e   the estimators  and
                                                                                               –x
                                    confidence intervals for E(C SPTF   C LPTF )  when we do not, resp. do, use common random numbers.
                                                          max   max
                                    We conclude that in this example the use of common random numbers reduces the standard
                                    deviation of the estimator and hence also the length of the confidence interval with a factor 5.

                                          Table 11.1: Estimation of  E(C SPTF    C LPTF )   without using  common random  numbers
                                                                 max   max










                                                Table  11.2: Estimation  of E(CSPTF ) using  common random  numbers









                                    When we want to use common random numbers, the problem of synchronization can arise:
                                    How can we achieve that the same random numbers are used for the generation of the same
                                    random variables in the two systems?
                                    In the previous example, this synchronization problem did not arise. However, to illustrate this
                                    problem, consider the following situation. In a G/G/1 queueing system the server can work at
                                    two different speeds, v  and v . Aim of the simulation is to obtain an estimator for the difference
                                                       1    2
                                    of the waiting times in the two situations. We want to use the same realizations of the interarrival
                                    times and the sizes of the service requests in both systems (the service time is then given by the
                                    sizes of the service request divided by the speed of the server). If we use the program of the
                                    discrete event simulation of Section 3 of the G/G/1 queue, then we  get the synchronization
                                    problem because the order in which departure and arrival events take place depends on the
                                    speed of the  server. Hence,  also  the  order in  which interarrival  times  and  sizes of  service
                                    requests are generated depend on the speed of the server.
                                    The synchronization problem can be solved by one of the following two approaches:
                                    1.   Use separate random number streams  for the  different sequences  of random variables
                                         needed in the simulation.
                                    2.   Assure that the random variables are generated in exactly the  same order  in the  two
                                         systems.


                                           Example: The G/G/1 queue, the first  approach can  be realized by using a separate
                                    random number stream for the  interarrival times  and for the service  requests. The  second
                                    approach can be realized by generating the service request of a customer already at the arrival
                                    instant of the customer.

                                    11.3.2 Antithetic Variables

                                    The method of antithetic variables makes use of the fact that if U is uniformly distributed on
                                    (0, 1) then so is 1 – U and furthermore U and 1 – U are negatively correlated.




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