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Unit 6: Functions




                                                                                                Notes
                         1                1              1
                                                 x
          (d)  Let  ( )f x  ,  then  (f  ) x   f ( )     y   is an odd function and symmetric
                         x                x              x
               about origin.
               This, function is not  defined at  x = 0. Also the graph of this function  lies in I and  III
               Quadrants. When x > 0, then y approaches   for small values of x and approaches zero as
               x approaches  .
               Similarly, when x < 0, then y approaches –   as x approaches zero and approaches zero as
               x approaches –  . The broad graph of the function is shown in Figure 6.5.

                 Example

          Find inverse of the following functions and show that their graphs are symmetrical about the
          line y = x.

                   1
                                         2
          (a)  y     x  2         (b) y = x , x   0
                   3
          Solution:
          (a)  To find inverse of the given function, we solve it for x.
                 x = 3(y – 2)
               To draw  graph, we  take independent  variable on  x-axis and  dependent variable  on
               y-axis, therefore we interchange x and y in the above equation to get y = 3(x – 2) = 3x – 6.

                                         1
               The graphs of the functions  y  x  2  and y = 3x – 6 are shown in Figure 6.6. These are
                                         3
               symmetric about the line y = x. Also note that their point of intersection (3, 3) also lies on
               the line.

                                            Figure  6.6







                                         1
                                       y =    x + 2    (3, 3)
                                         3      2
                                –6           0
                                                      – 6
                                                    = 3

                                             –6






                                                         1
          (b)  Solving the given function for x, we get  x  y  y 2  ,  x   0.





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