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Basic Mathematics – I




                    Notes
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                                          Example 1: From point A, an observer notes that the angle of elevation of the top of a
                                   tower (C,D) is a (degrees) and from point B the angle of elevation is b (degrees). Points A, B and
                                   C (the bottom of the tower) are collinear. The distance between A and B is d. Find the height h of
                                   the tower in terms of d and angles a and b.













                                   Solution:
                                   1.   Let x be the distance between points B and C, hence in the right triangle ACD we have
                                       tan(a) = h / (d + x)

                                   2.   and in the right triangle BCD we have tan(b) = h / x
                                   3.   Solve the above for x x = h / tan(b)
                                   4.   Solve tan(a) = h / (d + x) for h h = (d + x) tan(a)
                                   5.   Substitute x in above by h / tan(b) h = (d + h / tan(b)) tan(a)

                                   6.   Solve the above for h to obtain. h = d tan(a) tan(b) / [ tan(b) - tan(a)]


                                   Problem 1: An aircraft tracking station determines the distance from a common point O to each
                                                                                                           o
                                   aircraft and the angle between the aicrafts. If angle O between the two aircrafts is equal to 49  and
                                   the distances from point O to the two aircrafts are 50 km and 72 km, find distance d between the

                                   two aircrafts.(round answers to 1 decimal place).
                                   Solution to Problem 1:

                                   1.   A diagram to the above problem is shown below




















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