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Unit 9: Correlation and Regression




                                                                                                Notes
               Example: Given the following data, compute the coefficient of correlation r,  between X
          and Y.
                       Age (yrs.)    30 -50      50 -70    70 -90   Total
                         Marks 

                           0 - 5      10            6         2       18
                          5 - 10      3             5         4       12
                          10 - 15     4             7         9       20
                          Total       17           18        15       50
          Solution:
          Note: Instead of doing the computation work in a single table, it can be split into the following
          steps:
          Taking mid-values of the class intervals, we have
                 Mid-values (X)  2.5   7.5    12.5

                 Mid-values (Y)  40    60      80
                     X - 7.5       Y -  60
          Let     u =  i     and  v =  i
                                 i
                   i
                        5            20
                various u values are :  – 1   0   1
          and    various v values are :  – 1   0   1
          1.   Calculation of f u v
                             ij i j















                        f u v  = 13
                          ij i j
          2.   Calculation of f u  and f u  2      3.  Calculation of f ¢v  and f ¢v  2
                            i i     i i                                j  j   j  j
                                                                          2
                                     2                  v      ¢ f  ¢ f v  ¢ f v
                   u i   f i  f i u i  f i u i           j    j    j  j  j  j
                   - 1  18   - 18  18                   –1   17   – 17   17
                    0   12     0    0                     0   18    0     0
                    1   20    20   20                    1    15    15   15
                  T otal  50   2   38                  T otal  50  – 2   32
          Substituting these values in the formula of r, we have

                             -
                        50 13 2 ´ ( ) 2-     654
                          ´
                 r =                    =           = 0.376
                                     -
                                 ´
                           -
                        ´
                      50 38 4 50 32 4      1896 1596
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