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Unit 12: Hypothesis Testing




                                                                                                Notes
                                             -
                                           x y
                                     t =
                                           æ  1  1 ö
                                         s 2 ç è n 1  +  n 2 ø ÷
          Here                      n  = 5  n  = 7
                                     1     2
                                   x = 230,  y = 399

                                 2
                                        
                           ( x x-  ) = 310 , ( y -  ) y  2  = 399
                                         x  230
                                    x  =  n  =  5  =  46
                                         1
                                         y  399
                                    y  =   =    =  57
                                        n 2  7

                                           1            2        ) }
                                                                 2
                                    s  =           ( {å  x -  ) x + å ( y -  y
                                     2
                                        n +  n -  2
                                         1  2
                                  D.F. = (n  + n  – 2) = (5 + 7 – 2) = 10
                                         1   2
                                        1
                                    s  =  {310 674+  } 98.4=
                                     2
                                        10
                                              -
                                           46 57
                                     t =
                                              æ  1  1ö
                                         98.4 ´ ç  + ÷
                                              è  5  7 ø
                                            - 11
                                      =       æ  12 ö
                                         98.4 ´ ç  ÷
                                              è 35 ø
                                         - 11    11
                                      =       = -
                                         33.73   5.8
                                      = – 1.89
          t at 10 d.f. at 5% level is 1.81.
          Since, calculated t is greater than 1.81, it is significant. Hence H  is accepted. Therefore the two
                                                             A
          nutrition programmes differ significantly with respect to weight increase.

          Two Tailed t-Test

          When two samples are related we use paired t-test for judging the significance of the mean of
          difference of the two related samples. It can also be used for judging the significance of  the
          coefficients of simple and partial correlations.
          The t-test is performed using the following formula;
                                                 n -  2
                                           t =  r
                                              yx  -
                                                 1 r yx





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