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Unit 3: Linear Programming Problem – Simplex Method




                                                                                                Notes
                              Figure  3.7:  The Reddin  Problem—Infeasibility

                         10000
                       X 2
                          9000
                                                           Processing Constraint
                          8000

                          7000
                                                        Demand Constraint
                          6000
                          5000

                          4000                             Combined Machine
                                                           Feasible Region
                          3000
                          2000
                                                             Assembly Constraint
                          1000

                                 1000 2000 3000 4000 5000 6000 7000 8000 9000 10000
                                                                      X 1
          The graphical presentation of the Reddin Problem in Figure shows that the combined machine
          feasibility region does not permit the production of 6,500 units of product A. Thus, the demand
          constraint and the machine capacity constraints are mutually conflicting, resulting in infeasibility.
          Let us try to solve this problem by the simplex method. It is formulated below in the standard
          simplex form.
          Row 1: P-      5x  – 4x             -50a   = 0
                          1    2                  1
          Row 2:           2x  + 1x  + s           = 10,000
                             1   2   1
                                3
          Row 3:           2x  +   x  + s         = 12,000
                             1  2  2     2
          Row 4:            x               + a    = 6,500
                             1                 1
          Artificial variable a1 has been assigned a coefficient of 50 in the objective function.
          Towards The First Basis

          Row 4 × 50:         50x         + 50a  = 325,000
                              1        1
          Old Row 1:     Z – 5x    – 4x  - 50a  = 0
                             1     2       1
          New Row 1:     Z + 45x  – 4x        = 325,000
                              1    2
                                      Table 3.2:  The First  Basis
                      Row 1: P  + 45x   – 4x                     = 325,000
                                    1      2
                      Row 2:      2x     + x    + s               = 10,000
                                    1      2      1
                      Row 3:      2x     + x            +s        = 12,000
                                    1      2              2
                      Row 4:        x                          +a  = 6,500
                                    1                            1






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