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Unit 14: Poisson Probability Distribution




          14.1.3 Poisson Approximation to Binomial                                              Notes

          When n, the number  of trials become large, the  computation  of probabilities  by using the
          binomial probability mass function becomes a  cumbersome task.  Usually, when  n    20 and
          p    0.05 , Poisson distribution can be used as an approximation to binomial with parameter m
          = np.


                 Example: Find the probability of 4 successes in 30 trials by using (1) binomial distribution
          and (2) Poisson distribution. The probability of success in each trial is given to be 0.02.

          Solution:
          1.   Here n = 30 and p = 0.02
                         30      4     26
                   P r  4  C 0.02  0.98    27405 0.00000016 0.59  0.00259.
                            4
          2.   Here m = np = 30 × 0.02 = 0.6
                           0.6   4
                         e    0.6   0.5488 0.1296
                   P r  4                         0.00296.
                             4!          24
          14.1.4 Fitting of a Poisson Distribution

          To fit a Poisson distribution to a given frequency distribution, we first compute its mean  m.
          Then the probabilities of various values of the random variable  r are computed by using the

                                     e  m .m r
          probability mass function  P r  .  These probabilities are then multiplied by N, the total
                                        ! r
          frequency, to get expected frequencies.


                 Example: The following mistakes per page were observed in a book:
                                 No. of mistakes per page :  0  1  2  3
                                       Frequency      : 211 90 19 5

          Fit a Poisson distribution to find the theoretical frequencies.
          Solution:
          The mean of the given frequency distribution is

                                      0×211+1×90 + 2×19 + 3×5  143
                                  m =                       =   = 0.44
                                           211+90 +19 + 5    325
          Calculation of theoretical (or expected) frequencies

                           e  0.44  0.44  r
          We can write  P r          . Substituting  r = 0,  1, 2 and 3, we  get the probabilities for
                               r!
          various values of r, as shown in the following table.













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