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bdkbZµ25% vfrxq.kd ;k xq.kd&Rojd ijLij fozQ;k
D;ksafd Y = C + I uksV
blfy, DY = cDY + DIa + v DY
DY – c DY – v DY = DIa
DY(1 – c – v) = DIa
γ ∆ 1 1
∆ Ia = 1 cv s v
1 1
;k Ks =
1 cv s v
uksV~l vfrxq.kd crkrk gS fd ;fn Lok;Ùk fuos'k esa dksbZ izkjafHkd o`f¼ gksrh gS] rks vk; esa Lok;Ùk fuos'k dh
Ks xq.kk o`f¼ gks tk,xhA
tgk¡ Ks vfrxq.kd gS] c lhekar miHkksx izo`fÙk gS] v lhekar fuos'k izo`fÙk vkSj s lhekar cpr izo`fÙk (s = 1 – c)
gSaA
vfrxq.kd crkrk gS fd ;fn Lok;Ùk fuos'k esa dksbZ izkjafHkd o`f¼ gksrh gS] rks vk; esa Lok;Ùk fuos'k dh Ks
xq.kk o`f¼ gks tk,xhA bl izdkj] lkekU; :i esa vfrxq.kd gksxk]
1
DY = D Ia
1 c v
= Ks D Ia
vc ge mi;qZDr lehdj.k osQ :i esa xq.kd rFkk Rojd osQ fefJr dk;Zdj.k dh O;k[;k djrs gSaA eku yhft,
fd c = 0.5, v = 0.4 vkSj Lok;Ùk fuos'k esa #i;s 100 djksM+ dh o`f¼ gksrh gS] rks leLr vk; esa o`f¼
DY = × 100
1
= × 100 = 10 × 100 = 1000.
0.1
;g n'kkZrk gS fd Lok;Ùk fuos'k esa 100 djksM+ #i;s dh o`f¼ us vk; dks c<+kdj 100 djksM+ #i;s dj fn;k
gSA lkèkkj.k xq.kd us vk; dks osQoy c<+kdj 200 djksM+ #i;s dj fn;k gksrk] ;g ekudj fd
Lo&ewY;kadu (Self Assessment)
fjDr LFkkuksa dh iw£r djsa (Fill in the blanks) :
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1- xq.kd vkSj Rojd dk bdêòk izHkko dgykrk gSA
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2- yhoj izHkko vFkZO;oLFkk dks vk; iztuu osQ cgqr Å¡ps ;k Lrj ij ys tk ldrk gSA
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