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Statistical Methods in Economics


                   Notes          The test is not satisfied by any of the Laspeyre’s, Paasche’s or Fisher’s Method. However, the simple
                                  aggregative method and the fixed weight aggregative method (Kelly’s method) satisfy this test.
                                  Example 1:  Compute Fisher’s ideal number and prove that it satisfies factor reversal and time
                                              reversal test.
                                                                     Price                   Quantity
                                        Commodity
                                                               2002         2003        2002          2003

                                            A                  10            12          12            15
                                             B                  7            5           15            20
                                            C                   5            9           24            20
                                            D                  16            14           5             5
                                  Solution:

                                    Commodity       Price            Quantity
                                       Item      2002    2003     2002    2003     p q     p q     p q     p q
                                                                                                    nn
                                                                                            00
                                                                                    n0
                                                                                                            0n
                                        A         10      12       12      15      144     120     180      150
                                        B         7        5       15      20       75     105     100      140
                                        C         5        9       24      20      216     120     180      100
                                        D         16      14       5        5       70      80      70      80

                                                                                  Total  ∑ pq  ∑ pq  ∑ pq  ∑ pq
                                                                                                     nn
                                                                                                             0n
                                                                                             00
                                                                                     n0
                                                                                   505     425     530      470
                                              Fisher’s price index
                                                                         ∑  pq  ∑  pq
                                                                           n0
                                                                                  n n
                                                                   F
                                                             F p =  P on   =   ∑  pq  ⋅  ∑  pq  ×  100
                                                                                  0 n
                                                                           00
                                                                   505  530
                                                                =     ×    ×  100
                                                                   425  470
                                                                =  1.188 1.128 100×  ×
                                                                = 115.8
                                              (i) Time reversal test

                                                                   ∑  0n  ∑ p q  p q
                                                                            0 0
                                                            P no  =   ∑  nn  ⋅  ∑ p q  p q
                                                                            n 0
                                                                   470  525
                                                                =     ×
                                                                   530  505

                                                                   505 530 470 429
                                                                              ⋅
                                                                          ⋅
                                                                      ⋅
                                                      ∴  P no  × P on  =   425 470 530 505
                                                                =  1 = 1





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