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Unit 6: Dispersion: Meaning and Characteristics, Absolute and Relative Measures of Dispersion including Range...


            Example 6:  Calculate Coefficient of range from the following distribution:              Notes

                                   Marks                       No. of Students
                                   25—30                             6
                                   30—35                             3
                                   35—40                            12
                                   40—45                             8
                                   45—50                            22
                                   50—55                             9
                                   55—60                             5
            Solution:   The above question can be calculated by:
                        (1)  Limits Method:     L = 60, S = 25

                                                    L – S  60 – 25  35
                                 Coefficient of Range =    =      =    = 0.411
                                                             +
                                                    L + S  60 25    85
                        (2)  Mid-Value Method:  L = 57.5, S = 27.5
                                                    L – S  57.5 – 27.5  30
                                 Coefficient of Range =    =         =    = 0.352
                                                    L + S  57.5 27.5  85
                                                               +
            Example 7:  Find out relative dispersion of range from the following frequency table:
                                Marks                            Frequency
                                 5—10                                4
                                10—15                                6
                                15—20                               20
                                20—25                                7
                                25—30                                5
                                30—35                                8
                                35—40                                6
                                40—45                                5
                                45—50                                2
            Solution:   For the calculation of relative dispersion of range, mean, median and mode will be
                        calculated.
                  Marks          f           c.f.        m.v.         dx         fdx
                  5—10           4            4           7.5         – 5        – 20
                  10—15          6            10         12.5         – 4        – 24
                  15—20          20           30         17.5         – 3        – 60
                  20—25          7            37         22.5         – 2        – 14
                  25—30          5            42         27.5         –1          – 7
                  30—35          8            50         32.5          0           0
                  35—40          6            56         37.5          1           6
                  40—45          5            61         42.5          2          10
                  45—50          2            63         47.5          3           6
                               N = 63                                              ∑  fdx  = – 103




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