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vFkZ'kkL=k esa lkaf[;dh; fof/;k¡




                    uksV          3. lekos'kh oxkZUrj (Inclusive Class Intervals)μ;fn oxkZUrj lekos'kh vk/kj ij gS rks lw=k rks ogh jgrk
                                  gS] ijUrq cgqyd Kkr djus ls igys vFkkZr~ vkUrj.kxu djrs le; mUgsa viothZ Js.kh esa cny ysuk pkfg,A ,slk
                                  u djus ij mÙkj xyr gks tk,xkA
                                  mnkgj.k (Illustration) 13: fuEu leadekyk ls cgqyd Kkr dhft,μ

                                      oxZ             1-5    6-10  11-15  16-20  21-25  26-30  31-35  36-40  41-45

                                      vko`fÙk          8     11     17     33    25     19    10     5      2

                                  gy (Solution): fujh{k.k ls Li"V gS fd 16—20 gh cgqyd oxZ gS D;ksafd bldh vko`fÙk vf/dre gSA pw¡fd
                                  ;s oxkZUrj lekos'kh gSa vr% bUgsa viothZ esa cnyuk t:jh gSA vkUrjx.ku djrs le; oxZ dh lhek,¡ 15.5-20.5

                                  gksaxhA
                                                         f −  f
                                  vr%         Z= l +     1   0    ×  l −  2  l 1   l = 15.5
                                                   1
                                                                                   1
                                                       f 2  1  −  f −  0  f 2
                                                           33 −  17
                                                = 15.5 +              ×  5         l = 20.5
                                                        2 ×  33 −  17 −  25        2
                                                        16 ×  5
                                              Z = 15.5 +                           f = 33
                                                         24                        1
                                                = 15.5 + 3.33                      f = 17
                                                                                   0
                                                                                   f = 24
                                                                                   2
                                  cgqyd (Z) = 18.83
                                  4. lap;h vko`fÙk Js.kh ;k caVu esa cgqyd (Mode in case of Cumulative Frequency Series)μ;fn
                                  vko`fÙk caVu lap;h vko`fÙk osQ vk/kj ij cuk gS rks cgqyd Kkr djus osQ fy, igys mls lkekU; vko`fÙk caVu
                                  esa cny ysaxsA
                                  mnkgj.k (Illustration) 14: fuEu Js.kh ls cgqyd Kkr dhft,μ

                                    oxZ vUrjky       0—10    10—20    20—30   30—40    40—50   50—60   60—70

                                    vko`fÙk            4       16       56      97      124     138      140
                                  gy (Solution):

                                  ;g ,d lap;h Js.kh gS ftls lkekU; vko`fÙk Js.kh esa cnyk tk,xkA

                                      oxZ            0—10    10—20    20—30   30—40    40—50   50—60   60—70

                                      vko`fÙk          4       12       40      41      27       14      02
                                  fujh{k.k }kjk Li"V gS fd 30—40 gh cgqyd oxZ gS] vr% lw=k esa ewY; j[kus ij
                                                       l = 30, f  = 41, f  = 40, f  = 27, i = 0
                                                        1     1     0     2
                                                                 f −  f                41 40
                                                                                         −
                                                                            i
                                                       Z= l +   f 2  1 −  f −  0  f  ×= 30 +  2 ×  41 40 −  27  ×  10
                                                           1
                                                                                         −
                                                                1
                                                               10   0   2
                                                         = 30 +    = 30 + 0.67
                                                               15
                                                       Z = 30.67
                                  cgqyd ewY; = 30.67


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