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Complex Analysis and Differential Geometry                      Richa Nandra, Lovely Professional University




                    Notes                   Unit 12: Fundamental Theorem of Algebra




                                     CONTENTS
                                     Objectives

                                     Introduction
                                     12.1 Fundamental Theorem of Algebra
                                     12.2 Calculus of Residues
                                     12.3 Jordan’s Inequality
                                     12.4 Multivalued Function and its Branches

                                     12.5 Summary
                                     12.6 Keywords
                                     12.7 Self Assessment

                                     12.8 Review Questions
                                     12.9 Further Readings



                                   Objectives

                                   After studying this unit, you will be able to:
                                       Discuss the concept of fundamental theorem on algebra
                                   
                                       Describe the calculus of residues
                                   
                                       Discuss the multivalued functions and its branches
                                   
                                   Introduction

                                   In last unit, you have studied about the Taylor series, singularities of complex valued functions
                                   and use the Laurent series to classify these singularities. Also you studied about the concept
                                   related to argument principle and Rouche's theorem. This unit will explain fundamental theorem
                                   on algebra.

                                   12.1 Fundamental Theorem of Algebra

                                   Every polynomial of degree n has exactly n zeros.
                                   Proof. Let us consider the polynomial
                                                 a  + a  z + a  z  + …+ a  z , a   0
                                                                     n
                                                            2
                                                          2
                                                  0
                                                     1
                                                                   n
                                                                       n
                                   We take f(z) = a  z , g(z) = a  + a  z + a  z  +…+ a  z n-1
                                                                   2
                                                 n
                                                            1
                                                                         n-1
                                                                 2
                                                         0
                                               n
                                   Let C be a circle |z| = r, where r > 1.
                                   Now,               | f(z)| = |a  z | = |a | r n
                                                         n
                                                       n      n
                                                 |g(z)|  |a | + |a | r + |a | r +…+ |a | r n-1
                                                                         2
                                                          0     1     2         n-1
                                                               (|a | + |a | +…+ |a |) r n-1
                                                                1
                                                           0
                                                                         n-1
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