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Unit 21: New Spherical Indicatrices and their Characterizations




          It  is well-known  that for  a unit  speed  curve  with non-vanishing  curvatures the  following  Notes
          propositions hold:
          Proposition 1. Let  = (s) be a regular curve with curvatures K and T. The curve  lies on the
          surface of a sphere if and only if


                                                  '
                                          T    1 1  '  0.
                                                  
                                               
                                         K           
                                              T K   
                                              
          Proposition 2. Let  = (s) be a regular curve with curvatures K and T.  is a general helix if and
          only if
                                           K  constant.
                                           T  
          Proposition 3. Let  = (s) be a regular curve with curvatures K and T.  is a slant helix if and only
          if

                                          k 2      
                                                    ' 
                                   (s)      3    T    constant.
                                                   
                                                 K   
                                          2
                                              2 2
                                         (K  T )   
          21.2 Tangent Bishop Spherical Images of a Regular Curve
          Definition 2. Let  = (s) be a regular curve in E . If we translate of the first (tangent) vector field
                                                3
          of Bishop frame to the center O of the unit sphere S , we obtain a spherical image  = (s ). This
                                                   2
                                                                                 
          curve is called tangent Bishop spherical image or indicatrix of the curve  = (s).
          Let  = (s ) be tangent Bishop spherical image of a regular curve  = (s). One can differentiate of
                  
           with respect to s :

                                       '=  d  ds     k M  K M .
                                                 1
                                                          2
                                                   1
                                        ds ds
                                                       2
                                          
          Here, we shall denote differentiation according to s by a dash, and differentiation according to
          s  by a dot. In terms of Bishop frame vector fields, we have the tangent vector of the spherical
           
          image as follows:
                                             k M  k M
                                         T   1  1  2  2  ,
                                          
                                                 2
                                               k  k 2 2
                                                 1
          where
                                        ds     k  k  k(s).
                                               2
                                                  2
                                        ds     1  2
          In order to determine the first curvature of , we write
                                       k 3    k  '    k 3   k  '
                                 T
                             
                             T       2  2 2   1    M   1  2 2   2   M .
                                                                   2
                                                  1
                              
                                                      2
                                      2
                                    (k  k )   k 2   (k  k )   k 1 
                                                          2
                                      1
                                          2
                                                      1
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