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Complex Analysis and Differential Geometry




                    Notes          A regular curve C is parametrized by the arc-length parameter s, that is, c : L  En (L    s  c(s)
                                                                    dc                            dc(s)
                                    En)([1]). Then the tangent vector field    along C has unit length, that is,    1 for all
                                                                    ds                             ds
                                   s  L.
                                   Hereafter, curves considered are regular C -curves in E  parametrized by the arc-length parameter.
                                                                             n
                                                                   
                                                                                   dc(s)
                                   Let C be a curve in E , that is, c(s)  E  for all s  L. Let t(s) =    for all s  L. The vector field
                                                   n
                                                                n
                                                                                    ds
                                   t is called a unit tangent vector field along C,  and we assume that  the curve  C satisfies the
                                   following conditions (C ) ~ (C ):
                                                           n–1
                                                      1
                                                                 dt(s)  d c(s)
                                                                         2
                                                      (C ) : k (s)   ds    ds 2   0  for all s L.
                                                                                        
                                                        1
                                                            1
                                   Then we obtain a well-defined vector field n  along C, that is, for all s  L,
                                                                      1
                                                                        1   dt(s)
                                                                 n (s)  k1(s) .  ds  ,
                                                                  1
                                   and we obtain,
                                                            t(s),n (s)  0,  n (s),n (s)  1.
                                                                           1
                                                                                1
                                                                1
                                                                dn (s)
                                                                  1
                                                     (C ) : k (s)   ds    k (s).t(s)  0  for all s L.
                                                                                          
                                                       2
                                                                       1
                                                          2
                                   Then we obtain a well-defined vector field n  along C, that is, for all s  L,
                                                                      2
                                                                   1   dn (s)       
                                                           n (s)    .   1   k (s).t(s) ,
                                                                                     
                                                             2
                                                                               1
                                                                 k (s)   ds         
                                                                  2
                                   and we obtain, for i, j = 1, 2,
                                                           t(s),n (s)  0,  n (s),n (s)   ij ,
                                                                           i
                                                                                j
                                                                i
                                   where   denotes the Kronecker’s symbol.
                                         ij
                                   By an inductive procedure, for   = 3, 4, ..., n – 2,
                                                              dn  (s)
                                                                                           
                                                                 
                                                    (C ) : k (s)    ds 1   k    1 (s).n    2 (s)  0 for all s L.
                                                      
                                                         
                                   Then we obtain, for    = 3, 4, ..., n – 2, a well-defined vector field  n  along C, that is, for all s  L
                                                                                        
                                                                1   dn  (s)           
                                                         n (s)    .     1   k     1 (s).n    2 (s) ,
                                                                                       
                                                          
                                                               k (s)   ds             
                                                                
                                   and for i, j = 1, 2, ..., n – 2
                                                            t(s),n (s)  0,  n (s),n (s)   ij .
                                                                                j
                                                                i
                                                                           i



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