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P. 358
Unit 29: Geodesics
Thus, we have: Notes
1 1 i j 1 i j i 1 k i j i y . j
j
g
,
ij
ij
ij,k
ij
2 g s 0 2 g s 0 2 ij s 0 g s 0 2 g y g
Since Y vanishes at the endpoints, we can substitute into E (0), and integrate by parts the second
term to get:
b d 1
i
i
E (0) g g ik,j k y . j
a dt ij 2
Since:
d i i g i k i 1 g i k ,
dt g g ij,k g 2 g ij,k kj,i
ij
ij
ij
We now see that:
i
m
j
E (0) b g 1 g g g k y dt b g ,Y dt.
a ij 2 mj,k kj,m mk ,j a
Since E (0) 0 for all vector fields Y along which vanish at the endpoints, we conclude that
0, and is a geodesic.
The Schwartz inequality implies the following inequality between the length and energy
functional for a curve .
Lemma 2. For any curve , we have
2
L 2E (b a),
with equality if and only if is parametrized proportionally to arc length.
Finally, the last lemma we state to prove Theorem 1, exhibits the relationship between the L and
E functionals.
Lemma 3. A locally energy-minimizing curve is locally length-minimizing. Furthermore, if is
locally length-minimizing and is a reparametrization of by arc length, then is locally
energy-minimizing.
Proof. Suppose that is locally energy-minimizing, and let be a fixed endpoint variation of .
For each s, let s (t):[a,b] U be a reparametrization of the curve t (t;s) proportionally to
arc length. Let (t;s) s (t), then it is not difficult to see, using say the theorem on continuous
dependence on parameters for ordinary differential equations, that is also smooth. By
2
Lemma 1, is a geodesic, hence by Lemma 5, L 2E (b a). It follows that:
2
2
2
2
L (0) L 2E (b a) 2E (0)(b a) 2E (s)(b a) L (s) L (s).
Thus, is locally length-minimizing proving the first statement in the lemma.
Now suppose that is locally length-minimizing, and let be a reparametrization of by arc
length. Then is also locally length-minimizing, hence for any fixed-endpoint variation of ,
we have:
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