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Unit 7: Modern Approach to Probability



            (i)  Let A be the event that the sum of spots is 5 and B be the event that their sum is 10. Thus,  Notes
                 we can write
                 A = {(1, 4), (2, 3), (3, 2), (4, 1)} and B = {(4, 6), (5, 5), (6, 4)}
                 We note that  A B b  g   , i.e. A and B are mutually exclusive.


                                                                 4  3   7
                   By addition theorem, we have  (A   ) B   P A  ( )  +    .
                                            P
                                                      ( ) P B+
                                                                36  36  36
            (ii)  Let C be the event that there is a doublet and D be the event that the sum is less than 6.
                 Thus, we can write
                 C = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)} and
                 D = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 1), (2, 2), (2, 3), (3, 1), (3, 2), (4, 1)}
                 Further,  C D b  g  = {(1, 1), (2, 2)}



                                                     6  10  2   7
                 By addition theorem, we have   (C   D )   +      .
                                           P
                                                    36  36  36  18
            Alternative Methods:
                 It is given that n(A) = 4, n(B) = 3 and n(S) = 36. Also n A B b
            (i)                                                 g  0 . Thus, the corresponding
                 nine-square table can be written as follows:

                                                  B B Total
                                           A     0   4   4
                                           A     3 29 32
                                          Total  3 33 36


                                                 29  7
            From the above table, we have  (A   B ) 1     .
                                      P
                                                 36  36
                 Here n(C) = 6, n(D) = 10,  n C D b
            (ii)                           g  2  and n(S) = 36. Thus, we have
                                                  C C Total
                                           D     2  8  10
                                           D     4 22 26
                                          Total  6 30 36



                                        22  7
            Thus,  (C   D ) 1 P C   (   D ) 1     .
                 P
                                        36  18
                   Example 26: Two unbiased coins are tossed. Let A  be the event that the first coin shows
                                                          1
            a tail and A  be the event that the second coin shows a head. Are A  and A  mutually exclusive?
                     2 1 b         1 b                           1     2
                                      A
                        A
            Obtain  P A  g  and  P A  g . Further, let A  be the event that both coins show heads and
                                                                               1 b
                                       2
                         2
                                                    1
                                                                                 A
            A  be the event that both show tails. Are A  and A  mutually exclusive? Find  P A  g  and
             2  1 b                            1     2                             2
                  A
            P A  g .
                   2
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