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Unit 24: Local Finiteness and Paracompactness




          The situation where  consists of the three sets  < V < W. The sets we have formed are disjoint.  Notes
          In fact, they are separated by a distance of at least 1/n. This means that if V and W are distinct
          elements of ,  then d(x, y) 1/n whenever x T  (V) and y T  (W).
                                                  n           n
          To prove this fact, assume the notation has been so chosen that V < W. Since x is in T (V), then x
                                                                              n
          is in S (V), so the 1/n-neighbourhood of x lies in V. On the other hand since V < W and y is in
               n
          T (W), the definition of the latter set tells us that y is not in V. If follows that y is not in the 1/n-
           n
          neighbourhood of x.
          The sets T ( ) are not yet the ones we want, for we do not know that they are open sets. (In fact,
                  n
          they are closed.) So let us expand each of them slightly to obtain an open set E (). Specifically,
                                                                         n
          let E ( ) be the 1/3 n-neighbourhood of T ( ); that is, let E ( ) be the union of the open balls
              n                             n             n
          B(x, 1/3n), for x  T ( ).
                          n
          In case U < V < W, we have the situation. The sets we have formed are disjoint. Indeed, if V and
          W are distinct elements of , we assert that d(x, y) 1/3n whenever x E (V) and y E (W); this
                                                                    n          n
          fact  follows at  once from the triangle  inequality. Note that for each V  , the set E (V) is
                                                                                 n
          contained in V.
          Now let us define
                                          = {E  ()|}.
                                         n   n
          We claim that E  is a locally finite collection of open sets that refines . The fact that E  refines 
                       n                                                      n
          comes from the fact that E (V) V for each V . The fact E  is locally finite comes from the fact
                               n                          n
          that for any x in X, the 1/6n - neighbourhood of x can intersect at most one element of E .
                                                                                 n
          Of course, the collection  , will not cover X. But we assert that the collection
                               n
                                            E    n
                                               n   
          does cover X.

          Let x be a point of X. The collection  with which we began covers X; let us choose  to be the
          first element of  (in the well-ordering <) that contains x. Since  is open, we can choose n so that
          B (x, 1/n)  . The, by definition, x S ( ). Now because  is the first element of  that contains
                                         n
          x, the point x belongs to T ( ). Then x also belongs to the element E ( ) of E , as desired.
                               n                                 n     n
          Self Assessment

          1.   Many spaces have countable bases; but no T  space has a locally finite basis unless it is
                                                   1
               discrete. Prove this fact.
          2.   Find a non-discrete space that has a countably locally finite basis but does not have a
               countable basis.

          24.2 Paracompactness


          Definition: A space X is paracompact if every open covering  of X has a locally finite open
          refinement B that covers X.


                 Example 2: The Space   n  is paracompact. Let X =   n . Let  be an open covering of X. Let
          B  = , and for each positive integer m, let B  denote the open ball of radius m centered at the
           0                                  m
          origin. Given m, choose finitely many elements of  that cover  B  and intersect each one with
                                                              m
          the open set  X B  m 1 ;  let this finite collection of open sets be denoted  . Then the collection
                          
                                                                     m
           =   is a refinement of . It is clearly locally finite, for the open set B  intersects only finitely
               m                                                   m
          many elements  of  , namely those elements belonging to  the collection     ... . Finally,
                                                                        1     m
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