Page 305 - DMTH504_DIFFERENTIAL_AND_INTEGRAL_EQUATION
P. 305

Differential and Integral Equation




                    Notes          Just as we deal with ordinary differential equation
                                                                                x
                                                  (D n  a D n  1  a D  n  2  ... a  n )y  =  f ( )
                                                       1
                                                              2
                                             d
                                   Where  D    , we shall  deal briefly with the corresponding  equation in two independent
                                            dx
                                   variables,
                                                                                  y
                                                                                x
                                            (D n  a D n  1 D a D n  2 D  2  ...  a D n ) z =  f ( , )      ...(6)
                                                                     n
                                                 1
                                                         2
                                   where  D    and  D    .
                                             x         y
                                   The simplest case is
                                                                 (D mD   )z = 0


                                   i.e                              m    z = 0
                                                                  x    y

                                   or                               (p mq ) = 0

                                                                               z        z
                                   where                                 p =    and q
                                                                               x        x
                                   or                                    z =   (y mx )

                                   This suggests what is easily verified, that the solution of (6) if  ( , ) 0f x y   is

                                                              Z =   1 (y m x )  2 (y m x ) ... (y m x )    ...(7)
                                                                                                n
                                                                          1
                                                                                    2
                                                                                          n
                                   where the constants  m m m 3  ,...,m  are the roots (supposed all different)
                                                         ,
                                                      ,
                                                     1
                                                                n
                                                        2
                                        m n  a m n  1  a m n  2  .... a  n  = 0                            ...(8)
                                                    2
                                             1
                                          Example: Solve
                                              3      3      3
                                               z  3   z  2   z   = 0
                                                     2
                                              x 3   x y    x y 2
                                                    2
                                   or         (D 3  3D D  2DD  2 )z = 0
                                   Now the roots of
                                                    m 3  3m 2  2m = 0

                                   or 0, 1 and 2. So the solution is
                                                                                       x
                                                                      y
                                                               z = F 1 ( ) F 2 (y x ) F 3 (y  2 )








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