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Unit 27: Volterra Integral Equations and Linear Differential Equations




          27.2 Conversion of Volterra Integral Equation of Second                               Notes
               Kind into a Differential Equation


          We have seen that a linear differential equation with initial conditions can be expressed into a
          Volterra integral equation. In this section we can show that an integral equation can also be
          converted into a linear differential equation. To see that we take up the following example.


                 Example: Convert the integral equation

                                      x
                                                          u
                  y ( )  3x  4  2 sin x  (x  ) u  2  3(x  ) u  2 y ( )du           ...(1)
                   x
                                     0
          into the linear differential equation.
          Before attempting the problem we know that
                                     t
                      t
                  d  b ( )          b ( )                   db         da
                                                        b
                              u
                                                      t
                                               u
                         t
                                                                   a
                                                                    t
                                          t
                           u
                                                                 t
                            y
                                             y
                                                         t
                                            u
                       K ( , ) ( )du    K ( , ) ( )du  K [ , ( )]  K [ , ( )]      ...(2)
                  dt  a ( )         a ( ) t  t              dt         dt
                      t
          using equation (2), differentiate (1) with respect to x, we have
                                                         x
                                                                    y
                                                                      u
                                                     x
                    x
                  y  ( )  3  2cos x  (x  ) x  2  3(x  ) x  2 y ( )  2(x  u ) 3 ( )du
                                                         0
                                        x
                                                   y
                                  y
                                    x
                    x
          or      y  ( )  3  2cos x  2 ( )  2(x  u ) 3 ( )du                       ...(3)
                                                    u
                                        0
          Differentiating (3) again, we have
                                                     x
                                                        y
                  y  ( )  2sin x  2 ( )  2(x  x ) 3 ( )  (2) ( )du
                                  x
                                                          u
                                                 x
                                               y
                               y
                    x
                                                     0
                                              x
                                                u
                                  x
                                      y
                    x
                                        x
                               y
          or      y  ( )  2sin x  2 ( )  3 ( )  2  y ( )du                         ...(4)
                                             0
          Differentiating equation (4) again, we have
                                   x
                     x
                                               x
                                         x
                                       y
                                              y
                  y  ( )  2cos x  2y  ( )  3 ( )  2 ( )
                     x
          or      y  ( )  2y  ( )  3 ( )  2 ( )  2cos x                            ...(5)
                            x
                                        x
                                       y
                                  x
                                y
          Self Assessment
          2.   Convert the integral equation
                                     x
                                                            u
               y ( )  2x 2  3x  3cos x  2(x  ) u  3  3 (x  ) u  2  6 y ( )du
                 x
                                     0
          27.3 Summary
              We have taken up the case  of  nth order differential  equation and have seen how  an
               integral equation can be established.
              There is a strong connection between the initial value differential equation and the Volterra
               integral equation of the second type or of first type.
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