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p
                                                                     Unit 8: Bounded Linear Functional on the L -spaces



          From (4) and (8) it finally follows that                                              Notes
                                     F  =   g  .
                                            q
          This completes the proof of the theorem.

          Approximation by Continuous Function

          Theorem 6: If f is a bounded measurable function defined on [a, b], then for given   > 0,   a
          continuous function g on [a, b], such that
                                  f – g   <
                                      2
                                         x
          Proof: Let               F (x) =  f(t) dt  where x   [a, b].
                                         a
                                         x h      x
          Then          |F (x + h) – F (x)| =   f(t) dt  f(t) dt
                                          a       a

                                         x h       x h
                                       =   f(t) dt   f(t) dt
                                          x        x
                                         Mh, where |f (x)|   M,   x   [a, b].
          Taking h <  , and Mh <  , we get
                              1
                           |x + h – x| <    | F (x + h) – F (x) | <
                                                           1
                                         F (x) is continuous on [a, b].

                                          x h
          Let                     G  (x) =  n  f(t) dt : x [a, b] and n  N;
                                   n
                                           x
                                                1
          then                    G  (x) =  n F x   F(x)    ( F (x) is continuous on [a, b]
                                   n
                                                n
                                                            G (x) is continuous on [a, b]   n)
                                                             n
                                         x
          Again, since             F (x) =  f(t) dt, x [a, b].
                                         a
                                   F (x) = f (x) a.e. in [a, b].

                                             F(x (1/n) F(x)
          Now,                Lim G (x) =  Lim
                                   n
                              n          n        1/n
                                             F(x h) F(x)    1
                                       =  Lim           , h
                                         h  0     h         n
                                       = F  (x) = f (x) a.e. in [a, b]
                                     2
          and hence    Lim G (x) f(x)  = 0.
                             n
                        n



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