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Unit 8: Bounded Linear Functional on the L -spaces
                                                                                                        p



                                                                                                Notes
                          q 1
                                       q 1
          Now          |  |  sgn  k |  |    sgn  k
                k  k  k  k            k
                                       = | |  = | | p                             … (7)
                                            q
                                   k  k    k     k
                                                            (Using property of sgn function)
                                                 1
                                           n     p
                                     x  =   | | p
                                              k
                                          k 1
                                                 1
                                           n     p
                                     x  =   | | p
                                              k
                                          k 1
                                                  1
                                           n     q
                                       =    |  k | q                              … (8)
                                          k 1
          Since we can write
                                          n
                                     x =     e , we get
                                             k  k
                                         k 1
                                          n        n
                                   f (x) =   k f(e )  k  k
                                                k
                                         k 1       k 1
                                          n
                                   f (x) =   |  | q                      (Using (7))  … (9)
                                             k
                                         k 1
          We know that for every x    p

                                | f (x) |   f      x  ,
          which upon using (8) and (9), gives

                                                             1
                                          n           n      p
                                 |f (x)|    |  k | q  f  |  k | q
                                         k 1          k 1
          which yields after simplification.

                                     1
                              n      p
                               |  | q
                                  k       f                                      … (10)
                              k 1
          Since the sequence of partial sum on  the L.H.S. of (10) is bounded;  monotonic increasing, it
          converges. Hence

                                     1
                              n      p
                               |  | q
                                  k       f                                      … (11)
                              k 1
          So the sequence ( ) which is the image of f under T belongs to     and hence T is well defined.
                         k                                    q



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