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Measure Theory and Functional Analysis




                    Notes
                                                                          1        1
                                                                   n     q   n     p
                                                         |f (x)|    |y | q   |x | p
                                                                       i        i
                                                                   i 1      i 1
                                       Using the definition of norm for f, we get

                                                                          1
                                                                   n     q
                                                              f     |y | q                                … (2)
                                                                       i
                                                                   i 1
                                       Consider the vector, defined by

                                                                 |y | q
                                                             x =   i  , y  0  and x  = 0 if y = 0          … (3)
                                                                  y  i
                                                              i        i        i     i
                                                                         1             1
                                                                   n     p    n  |y | q  p  p
                                       Then,                 x   =   |x | p       i                       … (4)
                                                                      i
                                                                                   i
                                                                   i 1       i 1  |y |
                                       Since q = p (q – 1) we have from (4),

                                                                          1
                                                                   n     q
                                                             x  =   |y | q                                 … (5)
                                                                       i
                                                                   i 1
                                                                  n        n   q
                                                                            |y |
                                       Now                 f (x)  =   x y  i  y i  y i                    … (4)
                                                                     i
                                                                  i 1     i 1  i
                                                                  n
                                                               =    |y | q                               (By (3))
                                                                      i
                                                                  i 1
                                       So that

                                                         n
                                                             q
                                                          |y | = |f (x)     f      x                       … (6)
                                                            i
                                                        i 1
                                   From (5) and (6) we get,
                                                              1
                                                      n     1  p
                                                       |y | q      f
                                                         i
                                                      i 1

                                                              1
                                                       n      q
                                                         |y | q     f                                      … (7)
                                                           i
                                                       i 1
                                       Also from (2) and (7) we have

                                                                          1
                                                                   n      q
                                                              f  =   |y | q  , so that
                                                                       i
                                                                   i 1




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