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Unit 9: Measure Spaces




          (c)  A measure   on a  -algebra  of subsets of a set X is called a  -finite measure if there exists  Notes
               a sequence (E  : n   ) in  such that    E  = X and   (E ) <   for every n   . In this case
                          n                  n     n       n
               (X, ,  ) is called a  -finite measure space.
          (d)  A set D    in an arbitrary measure space (X, ,  ) is called a  -finite set if there exists a
               sequence (D  : n   ) in such that U   D  = D and   (D ) <  for every n   .
                         n                   n     n         n
          Lemma 1: (a) Let (X, ,  ) be a measure space. If D    is a  -finite set, then there exists an
          increasing sequence (F  : n   ) in  such that  limF  D  and   (F ) <   for every n    and there
                            n                     n           n
                                               n
          exists a disjoint sequence (G  : n   ) in such that    G  = D and   (G ) <   for every n   .
                                 n                   n   n          n
          (b)  If (X, ,  ) is a  -finite measure space then every D    is a  -finite set.
          Proof 1: Let (X, ,  ) be a measure space. Suppose D    is a  -finite set. Then there exists a
          sequence (D  : n   ) in  such that U   D  = D and   (D ) <  for every n   . For each n   ,
                    n                   n     n        n
          let  F  U  n  D . Then (F  : n   )  is an increasing  sequence in   such that  limF  U  F
              n   k 1  k      n                                               n   n   n
                                                                           n
                                   n
            U n   D n  D  and  (F )   D k  n  (D )   for every n   .
                            n
                                               k
                                  k 1     k 1
          Let G  = F  and G  = F \ U n 1  F  for n   2. Then (G : n   ) is a disjoint sequence in  such that
               1  1     n   n  k 1  k             n
          U   G   U   F   D  as in the proof of Lemma “let (E  : n   ) be an arbitrary sequence in an
            n   n  n   n                            n
          algebra of subsets of a set X. Then there exists a disjoint sequence (F : n   ) in such that
                                                                  n
                     N     N
                       n 
               (1)     E     F  for every N   ,
                              n
                    n 1    n 1
                    and
                       n 
               (2)     E    F ”.
                             n
                    n    n 

                      (G ) =   (F ) <   and  (G )  F    n 1 F  (F )   for n   2. This proves (a).
                       1     1            n     n   k 1  k  n

          2.   Let (X, ,  ) be a  -finite measure space. Then there exists a sequence (E  : n   ) in  such
                                                                        n
               that U   E  = X and   (E ) <  for every n   . Let D   . For each n   , let D  = D   E .
                    n     n       n                                          n      n
               Then (D  : n   ) is a sequence in such that U   D  = D and m (D )    (E ) <   for every
                     n                              n   n          n     n
               n   . Thus D is a  -finite set. This proves (b).
          9.1.1 Null Set in a Measure Space

          Definition: Given a measure   on a  -algebra  of subsets of a set X  .  A subset E of X is called a null
          set with respect to the measure   if E    and  (E) = 0. In this case we say also that E is a null set
          in the measure space (X, ,  ). (Note that   is a null set in any measure space but a null set in a
          measure space need not be  .)
          Theorem 1: A countable union of null sets in a measure space is a null set of the measure space.
          Proof: Let (E  : n   ) be a sequence of null sets in a measure space (X, , ). Let E = U   E . Since
                    n                                                        n   n
           is closed under countable unions,
          we have E   .





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