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P. 150
Unit 12: General Convergence Theorems
Notes
= (f f) (f f) as (E – A) A =
n n
E A A
1 f f
2mE n
E A A
m(E A) 2M 1
2mE
A
mE 2M mA as m (E – A) mE
2mE
< 2M
2 4M
=
2 2
=
Thus f n f <
E E
But was arbitrary
lim f = f
n n
E E
12.1.5 Fatou’s Lemma
If {f } is a sequence of non-negative measurable functions and f (x) f (x) almost everywhere on
n n
a set E, then
f lim f
n
n
E E
i.e. f lim inf f
n n
E E
Proof: Since integrals over sets of measure zero are zero.
Without loss of generality, we may assume that the convergence is everywhere. Let h be
a bounded measurable function with h f and h (x) = 0 outside a set E E of finite
measure.
Define a function h by
n
h (x) = Min. {h(x), f (x)}
n n
then h (x) h(x) and h (x) f (x)
n n n
h is bounded by the boundedness of h and vanishes outside E as x E – E h(x) = 0
n
h (x) = 0 because
n
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