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Measure Theory and Functional Analysis




                    Notes
                                                               =  lim f n
                                                                 n
                                                                    E

                                                                 lim f as E   E
                                                                      n
                                                                 n
                                                                    E
                                                             h   lim f
                                                                      n
                                                                 n
                                                            E       E
                                   Taking supremum over all h   f, we get

                                                        sup h    lim f n
                                                                 n
                                                            E       E

                                                             f   lim f n                                   … (1)
                                                                 n
                                                            E       E
                                   Since {f } is monotonically increasing sequence and f     f
                                         n                                   n
                                                             f   f
                                                              n
                                                             f     f
                                                             n

                                                        lim f      f                                       … (2)
                                                         n   n

                                          From (1) and (2), we have

                                                             f   lim f   lim f   f
                                                                      n      n
                                                                 n       n
                                                             f   lim f
                                                                 n    n


                                   Theorem 2: Let {u } be a sequence of non-negative measurable functions, and let f =   u .
                                                 n                                                           n
                                                                                                        h 1
                                   Then  f     u  n
                                            h 1
                                                              n
                                   Proof: Let f  = u  + u  + … + u  =   u
                                            n  1   2      n        j
                                                              j 1
                                   then f     f
                                       n
                                   i.e.   lim f  f
                                          n   n
                                   Let h be a bounded measurable function with h   f and h(x) = 0 outside a set E   E of finite
                                   measure.
                                   Define a function h  by
                                                  n
                                                           h (x) = Min. {h (x), f (x)}
                                                            n              n


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