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Unit 12: General Convergence Theorems




                                                                                                Notes
          But                   lim f  =  lim f  lim f
                                     n       n       n
                                   E        E      E

          Hence                      f =  lim f .
                                              n
                                    E       E

          Corollary: Let {u } be a sequence of integrable functions on E such that   u  converges a.e. on
                        n                                              n
                                                                    n 1
                                                           n
          E. Let g be a function which is integrable on E and satisfy   u  g  a.e. on E for each n. Then
                                                              i
                                                          i 1

              u  is integrable on E and   u  n  u .
               n
                                                 n
           n 1                      E  n 1  n 1 E
                    n
          Proof: Let   u  f .
                       i  n
                   i 1
          Applying Lebesgue Dominated Convergence Theorem for the sequence {f }, we get
                                                                      n
                      u       u
                       n       n
                  E  n 1  n 1 E
          Corollary: If f is integrable over E and {E } is a sequence of disjoint measurable sets such that
                                            i
             E   E , then
              i
           i 1


                   f      f
                  E   i 1 E i
          Proof: Since {E } is a sequence of disjoint measurable sets, we may write.
                      i
                 f =   f
                          E i
                     i 1

          The function f.   E i   is integrable over E since  f  E i  |f| and |f| is integrable over E. Moreover


                   n
                     f    |f|, n N
                        E i
                   i 1
          Thus the conditions of above corollary are satisfied and hence


                                     f =     f
                                                E i
                                    E    E  i 1






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