Page 197 - DMTH505_MEASURE_THEOREY_AND_FUNCTIONAL_ANALYSIS
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Measure Theory and Functional Analysis




                    Notes              For x   , we have defined
                                               n
                                               p
                                                                         1
                                                                   n     p
                                                                       p
                                                            x  =     x i
                                                                   i 1
                                                     n       n
                                       Now |f (x)| =   x y  i  x y  i
                                                       i
                                                                i
                                                    i 1     i 1
                                       By using Hölder’s inequality, we get
                                                                         1        1
                                                         n         n     p  n     q
                                                                       p        q
                                                           x y       x        y
                                                            i  i      i        i
                                                         i 1       i 1     i 1
                                       so that
                                                                         1        1
                                                                   n     q  n     p
                                                                       q        p
                                                         |f (x)|     y i      x i
                                                                   i 1      i 1
                                       Using the definition of norm for f, we get

                                                                         1
                                                                   n     q
                                                                       q
                                                            f        y i                                   … (2)
                                                                   i 1
                                       Consider the vector, defined by

                                                                    q
                                                                  y i
                                                             x =     , y    0  and  x  = 0  if y  = 0      … (3)
                                                              i   y    i        i     i
                                                                   i
                                       Then

                                                                                      1
                                                                         1          p
                                                                   n     p    n   q   p
                                                                       p        y  i
                                                            x  =     x  i                                  … (4)
                                                                   i 1        i 1  y  i
                                       Since q = p (q – 1) we have from (4),
                                                                         1
                                                                   n     p
                                                                       q
                                                            x  =     y i                                   … (5)
                                                                   i 1
                                       Now

                                                                  n        n   q
                                                                             y  i
                                                         |f (x)| =   x y  i     y  i
                                                                     i
                                                                             y
                                                                  i 1     i 1  i
                                                                  n
                                                                      q
                                                               =    y i ,                                (By (3))
                                                                  i 1




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