Page 199 - DMTH505_MEASURE_THEOREY_AND_FUNCTIONAL_ANALYSIS
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Measure Theory and Functional Analysis




                    Notes
                                                                  y
                                                             x =   i   when |y | =  max  y i
                                                              i   y i       i  1  i  n
                                       and x  = 0 otherwise.
                                            i
                                       From the definition, x  = 0    k   i. So that we have
                                                         k
                                                                  y
                                                            x  =   i   = 1
                                                                  y

                                                                   n
                                                   Further |f (x)| =   (x y )  i
                                                                        i  = |y |
                                                                      i
                                                                  i 1
                                                      Hence |y | = |f (x)|    f  x
                                                             i
                                                           |y |   f  or max. {|y |}                  [ ||x|| = 1]
                                                             i                i
                                                                 ||f||                                    … (10)
                                       From (8) and (10), we obtain
                                                           ||f|| = max. {|y |} so that
                                                                        i
                                       y    f is an isometric isomorphism of L  to   n 1  * .

                                       Hence    n  *  n  .
                                               1

                                               n
                                   (iii)  Let L =    with the norm
                                         x  = max {|x | : i = 1, 2, 3, …, n}.
                                                   i
                                       Now f defined in (1) above is continuous as in (1).
                                                                                           n
                                       Let L  represents the set of all continuous linear functionals on    so that
                                                             L =   n  * .

                                       Now we determine the norm of y’s which makes y    f as isometric isomorphism

                                                                   n       n
                                                         |f (x)| =   x y i   x y i .
                                                                      i
                                                                              i
                                                                  i 1      i 1
                                            n                 n
                                       But    x y i     max( x )  y i
                                               i
                                                           i
                                            i 1              i 1
                                       Hence we have
                                                                   n
                                                        | f (x) |    y i  x   so that
                                                                   i 1
                                                                  n
                                                            f       y  i                                  … (11)
                                                                  i 1



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