Page 303 - DMTH505_MEASURE_THEOREY_AND_FUNCTIONAL_ANALYSIS
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Measure Theory and Functional Analysis




                    Notes         = 2  A  – A
                                       n
                                     0 as n

                                     A A *   0 or A A* 0   A A *

                                     A is self-adjoint operator.
                                  This completes the proof of the theorem.
                                  Theorem 2: Let S be the set of all self-adjoint operators in  (H). Then S is a closed linear subspace
                                  of  (H) and therefore S is a real Banach space containing the identity transformation.
                                  Proof: Clearly S is a non-empty subset of  (H), since O is self adjoint operator i.e. O   S.

                                     H , since O is self adjoint operator i.e. O S.

                                  Let  A ,A  2  S, We prove that A 1  A  2  S.
                                       1
                                   A ,A 2  S  A * A  and A * 2  A  2                                       ...(1)
                                                   1
                                               1
                                    1
                                  For   ,  R, we have
                                    A  1  A *   A *    A  2  *
                                          2
                                                  1
                                                           A * 1  A * 2

                                                           A 1  A 2    ,  are real numbers,  ,

                                      A    A is also a self adjoint operator on H.
                                       1    2
                                     A ,A  S    A    A  S.
                                      1  2       1    2

                                     S is a real linear subspace of   H .

                                  Now to show that S is a closed subset of the Banach space   H . Let A be any limit point of S.
                                  Then   a sequence of operator A is such that A  A. We shall show that  A  S i.e. A  A *.
                                                             n           n
                                  Let us consider

                                   A A *    A A  n  A  n  A *

                                     A A n   A  n  A *


                                     A A n   A  n  A * n  A * n  A *

                                     A A n   A  n  A * n  A * n  A *

                                       A n  A  A  n  A n  A  n  A *     A  n  S  A * n  A  n


                                     A  n  A  0  A n  A






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