Page 280 - DSOC404_METHODOLOGY_OF_SOCIAL_RESEARCH_HINDI
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lkekftd 'kks/ dh i¼fr



                  uksV          laf{kIr fofèk }kjk gy
                                lw=kµ

                                                            ∑  fd ´ 2   ∑  fd ´  2
                                                     (s)=         −     
                                                              N      N 

                                ekuk fn, x, izkIrkadksa dk dfYir ekè; (A) = 10 gSA

                                           izkIrkad  vko`fÙk   dfYir ekè; A = 10     fxd´       fd´ xd´

                                             (x)       (f)   ls izkIRkkadksa dk fopyu d´ = fd´  = fd´ 2
                                             21        1               11             11         121
                                             20        0               10             0            0
                                             19        0               9              0            0
                                             18        2               8              16         128
                                             17        1               7              7           49
                                             16        2               6              12          72

                                             15        3               5              15          75
                                             14        2               4              8           32
                                             13        3               3              9           27
                                             12        4               2              8           16
                                             11        6               1              6            6
                                             10        8               0              0            0
                                              9        7              –  1            –  7         7

                                              8        5              –  2           –  10        20
                                              7        2              –  3            –  6        18
                                              6        1              –  4            –  4        16
                                              5        3              –  5           –  15        75
                                                                                            2
                                                (Nåf) = 50           åfd´ = 50           åfd´  = 662


                                                            ∑  fd ´ 2   ∑  fd ´  2
                                                     (s)=         −    
                                                              N       N 
                                                       2
                                                   åfd´ = 662,
                                                    åfd´ = 50,      N = 50

                                                            662   50  2
                                                     (s)=      −   
                                                            50    50

                                                                −
                                                        =   13.24 1




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