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Basic Mathematics – I




                    Notes                 4 1    3

                                             1  0  1
                                             2   1 1
                                         1
                                             5  2  0

                                         ( 1)(0 2) 0(0 5) 1( 4 5)

                                         2 0 1   3

                                            2   1 1
                                            0   2 1
                                         2
                                            1  5   0

                                         2(0 5) 1(0 1) 1(0 2)

                                          10 1 2    9

                                            2  0   1
                                            0   1  2
                                         3
                                            1  2   5
                                         2( 5 4) 0(0 2) 1(0 1)

                                          2 1    3

                                                 3
                                          x           1
                                                  3
                                                 9
                                         y   2      3
                                                 3

                                                 3
                                         z   3      1
                                                 3


                                          Example

                                            a   b  2     a 1 2  a 2 2  a b  a b
                                                                         2 2
                                                                   1 1
                                   Show that   1  1   =              2   2
                                            a   b      a b   a b    a   b
                                             2   2      1 1   2 2    1   2
                                   Solution:
                                                       a 1  b 1  a 1  a 2
                                   Let            D =  a   b    b   b
                                                        2   2    1   2

                                                       a 1  a 2  a 1  a  2  a 2 1  a 2 2  a b  a b
                                                                                         2 2
                                                                                   1 1
                                                   2
                                                  D  =  b  b  b   b                  2   2  .
                                                        1   2  1   2   a b  a b     b 1  b 2
                                                                             2 2
                                                                        1 1


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