Page 155 - DMTH201_Basic Mathematics-1

Basic Mathematics – I

Notes
Figure 5.23

4 3
or = 5 + 4 and = 2 .
1 1 2
4
We are given that the mid point of the segment of the required line between ( , ) and ( , )
1 1 2 2
is (1, 5). Therefore

1 2 = 1 and 1 2 5,
2 2
4 3
5 1 4 2
or + = 2 and 4 5,
1 2
2
or + = 2 and 20 3 = 20 ... (3)
1 2 1 2
Solving equations in (3) for and , we get
1 2
26 20 26 222
1 and 2 and hence, 1 5. 4 .
23 23 23 23
Equation of the required line passing through (1, 5) and ( , ) is

222
5 23 5
y 5 1 (x 1) or y 5 (x 1)
1 26
1 1
23
or 107x 3y 92 = 0,

which is the equation of required line.

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