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Unit 13: Inventory Control




                                                                                                Notes
                Example: A foundry regularly uses 1,000 folds per day for 250 days in a year. Folds can be
          purchased in the lots of 1,000 for ` 10 per lot or in lots of 10,000 for ` 96.10 per lot. Ordering costs
          are ` 10 per order and the holding costs of items in inventory are estimated to be 20% of cost per
          year.
          1.   What is the EOQ and associated annual cost assuming that only lots of 1,000 items are
               available?

          2.   What is the EOQ and the associated annual cost assuming that only lots of 10,000 items are
               available?
          3.   Compare the costs of the two answers above and state the optimal ordering policy for
               these folds assuming that lots of 1,000 or 10,000 items can be ordered.
          Solution:
          Step 1: Calculation of EOQ and the associated annual cost when only lots of 1,000 items are there

          1.   Usage per day 1,000 folds for 250 days
                                     = 1,000 × 250 days
                                     = 2,50,000 folds p.a.
          2.   Purchase price: ` 10 per lot of 1,000 folds

                                        `
                                     =       = ` 0.01 Per unit

          3.   Ordering cost ` 10 per order
          4.   Carrying cost is 20% p.a.
          Step 2: Calculation of EOQ and the associated annual cost when only lots of 10,000 items are
          there
          1.   Usage p.a 2,50,000 folds
          2.   Purchase price : ` 96.10 per lot of 10,000 folds

                                     = `        = ` 0.00961 per unit
          3.   Ordering cost ` 10 per unit
          4.   Carrying cost is 20% p.a.
          Step 3: Calculation of EOQ by using equation


                                EOQ  =

          1.   When purchase price is ` 0.01/unit
                                           `
                                     =
                                                `

                                     = 51,004 units










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