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VED1
          E\L-LOVELY-H\math6-1 IInd 6-8-11 IIIrd  24-1-12 IVth 21-4-12 Vth 20-8-12 VIth  10-9-12



          vFkZ'kkfL=k;ksa dk xf.kr




                   uksV                                                     dy                     dy
                                                             cos (a +  y ) cos y  −  sin . { sin (a +  y  −  y )}
                                                           (                dx                     dx
                                                                            cos (a +  ) y
                                                                               2
                                                                                              dy
                                                                                           y
                                                             {cos (a +  y ).cos y +  sin (a +  y ).sin }
                                                           (                                  dx
                                                                            2
                                                                          cos (a +  ) y
                                                                          dy
                                                             cos (a +  y −  ) y
                                                           (              dx
                                                                   2
                                                                cos (a +  ) y
                                                                cos a   dy
                                                           (
                                                                2
                                                             cos (a +  y ) dx
                                                       dy    cos (a +  ) y
                                                                2
                                ⇒                          (
                                                       dx       cos a
                                iqu% tc   ( +
                                rc 
 
   ( +  ⇒    ( 	π
                                                                2
                                                       dy     cos (a +π )
                                                                      n
                                  ( + ij]                  =
                                                       dx        cos a
                                                                2
                                                       dy     cos a
                                ⇒                          (
                                                       dx     cos a




                                mnkgj.k 9- ;fn       
                    rks fl¼ dhft,
                                                          2
                                                 ( −  1  2 dy  − x  x dy  = 4.
                                                       )
                                                        dx 2    dx



                                gy %                 (  
 
      ,
                                                       dy   (  2(sin −  1  x − cos −  1  ) x
                                                       dx           1 −  x 2
                                                     2 dy
                                ⇒                1 −  x    ( 2(sin −  1  x −  cos −  1  ) x
                                                       dx
                                  osQ lkis{k vodyu djus ij

                                         2
                                 1 −  x 2 dy  +  1   ( 2 ).  dy   (  2     1  +  1    
                                                         x
                                                      −
                                       dx 2  21 −  x 2      dx         1 −  x 2  1 −  x   2  
                                                       2
                                              (1 −  x 2 dy  −  x  dy
                                                    )
                                                     dx 2    dx   (  2.  2
                                                    1 −  x 2         1 −  x 2
                                                      2
                                                   2 dy      dy
                                ∴             (1 −  x  )  −  x   ( $
                                                     dx 2   dx
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