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vFkZ'kkL=k esa lkaf[;dh; fof/;k¡
uksV (d) vUr esa vxzfyf[kr lw=kksa esa ls fdlh ,d }kjk izeki fopyu Kkr dj ysrs gSaμ
∑ dx 2 ∑ F dx I 2 ∑ dx 2
izFke lw=kμσ = −G J K f}rh; lw=kμσ = − ( − X A) 2
N H N N
∑ 2 − dx ( − NX A) 2 1 2 2
r`rh; lw=kμσ = prqFkZ lw=kμσ = N.∑ − (∑ dx dx )
N N
;g jhfr lekUrj ekè; osQ n'keyo gksus dh fLFkfr esa T;knk mi;ksxh gSA bu pkjksa lw=kksa }kjk ifj.kke leku izkIr
gksrs gSaA izFke lw=k vf/d izpfyr gS] ijUrq prqFkZ lw=k dk iz;ksx djus ls milknu foHkze U;wure gksrk gS] D;ksafd
;g xq.kkRed lw=k gksrk gSA
izeki fopyu xq.kkad fdls dgrs gSa\
mnkgj.k (Illustration) 4:
fuEu leadksa ls izeki fopyu vkSj mldk xq.kkad Kkr dhft,μ
41, 44, 45, 49, 50, 53, 55, 55, 58, 60
gy (Solution): izeki fopyu dk y?kq jhfr }kjk ifjdyu
Øekad ewY; A = 50 ls fopyuksa osQ oxZ in&ewY;ksa osQ oxZ
2
2
(X) fopyu (dx) (d x) (X )
1. 41 – 9 81 1681
2. 44 – 6 36 1936
3. 45 – 5 25 2025
4. 49 – 1 1 2401
5. 50 0 0 2500
6. 53 + 3 9 2809
7. 55 + 5 25 3025
8. 55 + 5 25 3025
9. 58 + 8 64 3364
10. 60 + 10 100 3600
2
;ksx N = 10 ∑X = 510 ∑dx = + 10 ∑d x = 366 ∑X = 26366
2
izFke lw=kkuqlkjμ f}rh; lw=kkuqlkjμ
2
2
∑ dx ∑ F dx I 2 ∑ d X
σ = −G J K σ = − ( − X A) 2
N H N N
366 F 10I 2 366
−G J
− (
= 10 H 10K = 10 − 51 50) 2
= 36.6 − 1 = 36.6 − 1
= 35.6 = 35.6
σ = 5.97 σ = 5.97
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