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bdkbZ—10% lglaca/ % fo{ksi&fp=k fof/] dkyZ fi;lZu dk lglaca/ xq.kkad
uksV
Σd 2 180 Σd 2 y 158
.
σ = N x = 10 = 18 = 4.24 σ = N = 10 = 15 8 = 3.97
y
x
dkyZ fi;lZu lglEcU/ xq.kkad]
Σdd
r = x y
Nσσ y
x
95 95
= = = 0.56
.
10 × 4 24 × . 3 97 168 33
.
mnkgj.k (Illustration) 5: fuEu rkfydk ls okLrfod ekè;ksa X = 66 rFkk Y = 65 ls fopyu ysrs gq, dkyZ
fi;lZu osQ lglEcU/ xq.kkad dh x.kuk dhft,μ
x : 84 51 91 60 68 62 86 58 53 47
y : 78 36 98 25 ? 82 90 62 65 39
gy (Solution):
ekuk Js.kh y esa vKkr eku = a, rc
ΣY= NY ls
575 + a = 10 × 65
⇒ a = 650 – 575 = 75
x d = x – 66 d x 2 y d = y – 65 d y 2 d d
y
x y
x
84 18 324 78 13 169 234
51 – 15 225 36 – 29 841 435
91 25 625 98 33 1,089 825
60 – 6 36 25 – 40 1,600 240
68 2 4 75 10 100 20
62 – 4 16 82 17 289 – 68
86 20 400 90 25 625 500
58 – 8 64 62 – 3 9 24
53 – 13 169 65 0 0 0
47 – 19 361 39 – 26 676 494
660 65 – 65 = 0 2,224 575 + 75 98 – 98 = 0 5,398 2,704
= 650
Σdd
r = x y
Σ x 2 Σd × d 2 y
2 704 2704 2704
,
,
,
= = = = 0.78
.
,
,
.
2224 × 5 398 47 16 × 73 47 3464 84
,
,
mnkgj.k (Illustration) 6: uhps nh xbZ lwpuk ls dkyZ fi;lZu lglEcU/ xq.kkad ifjdfyr dhft,μ
Calculate Karl Pearson’s correlation from the information given below :
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