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bdkbZ—13% lk/kj.k izrhixeu xq.kkad fof/
gy (Solution): uksV
izrhixeu xq.kkadksa dh x.kuk
iRuh dh vk;q (o"kZ) ifr dh vk;q (o"kZ) X 2
;ksx dy fdy fdy fdxdy
Y 20–25 25–30 30–35
1 0
16–20 9 14 — 23 – 1 – 23 23 9
9 0
0 0 0
20–24 6 11 3 20 0 0 0 0
0 0 0
1
24–28 — — 7 7 1 7 7 7
7
;ksx 15 25 10 50 – 16 30 16
dx – 1 0 + 1 Σfdy Σfdy2 Σfdxdy
fdx – 15 0 0 – 5 Sfdx
fdx 2 15 0 10 25 Σfdx 2 ix = 6
fdxdy 9 0 7 16 Σfdxdy iy = 4
X dk Y ij izrhixeu xq.kkad
L Σ fdx fdyO
Σ
.
ix N M Σ fdxdy − N P Q
bxy = iy L Σ ( fdy O
2
)
2
N Σ M fdy − N P Q
− L 5 × − 16O
5 N M 16 − 50 Q P
= 4 L 16 O
2
M 30 − − ( ) P
N 50 Q
.
5 ( 16 − 16)
=
4 30 − 5 12)
.
(
5 14 4 .
= ×
4 24 88
.
7200
= = .72
.
99 52
X dh Y ij izrhixeu js[kk
X – X = bxy (Y – Y )
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