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bdkbZ—13% lk/kj.k izrhixeu xq.kkad fof/




            gy (Solution) :                                                                           uksV
                                       izrhixeu xq.kkadksa dk ifjdyu

                       (X – A)                 Blood      (Y – A)
               Age     A = 62                Pressure     A = 140
                X        dx         dx 2         Y          dy          dy 2     dxdy
               56        – 6         36        147           + 7        49         – 42
               42       – 20        400        125          – 15       225        + 300
               72      + 10         100        160         + 20        400        + 200
               36       – 26        676        118          – 22       484        + 572
               63        + 1          1        149           + 9        81          + 9
               47       – 15        225        128          – 12       144        + 180
               55        – 7         49        150         + 10        100         – 70
               49       – 13        169        145           + 5        25         – 65
               38       – 24        576        115          – 25       625        + 600
               42       – 20        400        140            0          0            0
               68        + 6         36        152         + 12        144         + 72
               60        – 2          4        155         + 15        225         – 30
               628     – 116       2672       1684            4       2502        1726

              Σx        Σdx        Σdx 2         Σy         Σdy       Σdy 2      Σdxdy

            X dk Y ij izrhixeu lehdj.k
                                     X – X = bxy (Y – Y )
                                             ΣX   628
                                        X =     =      = 52.33
                                             N     12
                                             ΣY   1684
                                        Y =     =       = 140.33
                                             N     12
                                             N.Σ       ( dx )( dy )
                                                       Σdxdy
                                                            Σ−
                                       bxy =
                                                         Σdy −
                                               N.Σ   2  ( dy ) 2
                                             12 ×  1726 −  ( 116)(4)
                                           =
                                               12 ×  2502 −  (4) 2
                                             20712 +  464
                                           =
                                             30024 −  16
                                             21176
                                           =        = .706
                                             30008
                                     X – X = bxy (Y – Y )
                                   X – 52.33 = .706 (Y – 140.33)
                                   X – 52.33 = .706Y – 99.07 + 52.33
                                         X = .706Y – 99.07 + 52.33
                                         X = .706Y – 46.74






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