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bdkbZ—13% lk/kj.k izrhixeu xq.kkad fof/
Σ Σdxdy dxdy Σdxdy uksV
= = =
.
nx 2 Σdx 2 Σdx 2
σ
n ×
n
Σdxdy Σdxdy
vFkkZr~ b = Σdy 2 ; b = Σdx 2
1
2
Σdxdy = X ,oa Y osQ okLrfod ekè; ls Kkr fopyuksa osQ xq.kuiQy dk ;ksx
2
Σdy = Y Js.kh osQ okLrfod ekè; ls Kkr fopyuksa osQ oxZ dk ;ksx
2
Σdx = X Js.kh osQ okLrfod ekè; ls Kkr fopyuksa osQ oxZ dk ;ksx
(2) tc dfYir ekè; ls fopyu fy, x, gksμtc okLrfod vadxf.krh; ekè; iw.kk±d esa u gksa rks ,sls le;
dfYir ekè; ls fopyu Kkr dj izrhixeu xq.kkadksa dk ifjdyu fd;k tkuk pkfg,A dfYir ekè; ls fopyu
Kkr fd, x, gksa rks fuEu lw=kksa dk iz;ksx fd;k tkuk pkfg,μ
X dk Y ij izrhixeu xq.kkad
σx
bxy = r
σy
( Σ Σdx)( dy)
Σdxdy − σ x
= N ×
N .σσ σ y
.
xy
( Σ Σdx)( dy)
Σdxdy −
= N
N .σ y 2
( Σ Σdx)( dy)
Σdxdy −
= L 2 Σdy F N 2 O
dyI
K
N M Σ −G J P
N M N H N Q P
( Σ Σdx)( dy)
Σdxdy −
N
= F ΣdyI 2
Σdy −G J
2
H N K
Σdxdy −
Σ
N.Σ ( dx ) ( dy )
=
Σdy −
N.Σ 2 ( dy ) 2
Y dk X ij izrhixeu xq.kkad
σy
byx = r
σx
( Σ Σdx)( dy)
Σdxdy − σ y
= N ×
N .σσ σ x
.
xy
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