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vFkZ'kkL=k esa lkaf[;dh; fof/;k¡




                    uksV            3.  v[kf.Mr Js.kh esaμblosQ ifjdyu dh nks jhfr;k¡ gSaμ
                                        (a) U;wure oxZ dh fupyh lhek dks U;wure ewY; vkSj vf/dre oxZ dh Åijh lhek dks vf/
                                           dre ewY; ekuk tkrk gSA

                                        (b) mPpre oxkZUrj osQ eè; ewY; dks vf/dre ,oa U;wure oxkZUrj osQ eè; ewY; dks U;wure
                                           ewY; eku ysrs gSaA
                                                               R = L – S

                                  fVIi.khμ(1) [kqys flj okys oxkZUrjksa esa foLrkj Kkr ugha fd;k tk ldrkA

                                         (2) lekos'kh oxkZUrj dks igys viothZ oxkZUrjksa esa cny ysrs gSaA
                                  foLrkj xq.kkadμfoLrkj vifdj.k dk ,d fujis{k eki gS tks rqyukRed vè;;u osQ fy, vuqi;qDr gS] vr%
                                  rqyuk djus osQ fy, foLrkj dk lkis{k eki Kkr fd;k tkrk gSA ;fn foLrkj dks pje inksa osQ ;ksx ls foHkkftr
                                  dj fn;k tk, rks mls foLrkj xq.kkad ;k ijkl xq.kkad dgrs gSaA
                                                                         L −  S
                                                       foLrkj xq.kkad (CR) =
                                                                         L +  S
                                  mnkgj.k (Illustration) 1: fuEu lead Js.kh dk foLrkj vkSj mldk xq.kkad Kkr dhft,μ
                                         20, 35, 25, 30, 16, 14, 13, 28, 38, 40, 10
                                  gy (Solution):

                                                             S = 10, L = 40
                                                         foLrkj = L – S = 40 – 10 = 30
                                                           L −  S  40  − 10  30
                                               foLrkj xq.kkad   =        =    = 0.6
                                                           L + S  40  + 10  50

                                  mnkgj.k  (Illustration) 2: fuEu caVu esa foLrkj o mlosQ xq.kkad dk ifjdyu dhft,μ
                                        oxZ%      0–5      5–10     10–15    15–20    20–25    25–30
                                        vko`fÙk%   4        8        5        15       10       11

                                  gy (Solution):
                                         I.         L = 30, S = 0     II.     L = 27.5 S = 2.5
                                           foLrkj L – S = 30  – 0 = 30           foLrkj = L – S = 27.5 – 2.5 = 25
                                                        L − S  30  − 0                 L − S   27.5 −  2.5  25
                                                    CR =     =        = 1         CR =       =          =
                                                        L + S  30  + 0                 L + S   27.5 +  2.5  30
                                                                                  CR = 0.83

                                  mnkgj.k (Illustration) 3: fuEu caVu ls foLrkj xq.kkad Kkr dhft,μ
                                        oxZ%      1—5      6—10    11—15    16—20    21—25    26—30

                                        vko`fÙk%   8        7        6        15       11       9
                                  gy (Solution) : lekos'kh oxkZUrjksa dks igys viothZ oxkZUrjksa esa cny fy;k tkrk gSA mDr leadksa esa U;wure
                                  lhek 0.5 o vfèkdre lhek 30.5 gSA






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