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bdkbZμ6: vifdj.k% vFkZ ,oa fo'ks"krk,¡] vifdj.k osQ lkis{k ,oa fujis{k eki] jsat] prqFkZd fopyu ,oa 'kred foLrkj
Q − Q 1 uksV
3
2 Q − Q 1
3
prqFkZd fopyu xq.kkad = =
Q + Q 1 Q + Q 1
3
3
2
mnkgj.k (Illustration) 5: fuEu nks Jsf.k;ksa esa vifdj.k dh rqyuk prqFkZd ekiksa }kjk dhft,μ
Å¡pkbZ (bap esa) % 58 56 62 61 63 64 65 59 62 65 55
Hkkj (ikS.M esa) % 117 112 127 123 125 130 106 119 121 132 108
gy (Solution):
prqFkZd ekiksa }kjk vifdj.k dh rqyuk osQ fy, prqFkZd fopyu xq.kkad Kkr fd;k tk,xkμ
Øe % 1 2 3 4 5 6 7 8 9 10 11
Å¡pkbZ % 55 56 58 59 61 62 62 63 64 65 65
Hkkj % 106 108 112 117 119 121 123 125 127 130 132
(A) Å¡pkbZ (B) Hkkj
Q = Size of G F N + I 1 J item Q = Size of G F N + I 1 J item
th
th
1 H 4 K 1 H 4 K
= Size of G F H 11 + I 1 J or 3 item = Size of G F H 11 + I 1 J or 3 item
4 K
4 K
rd
rd
Q = 58 Q = 112
1 1
3(N + 1) 3(N + 1)
th
Q = Size of item Q = Size of item
th
3 4 3 4
3(11 + 1) 3(11 + 1)
= Size of = 9 item = Size of = 9 item
th
th
4 4
Q = 64 Q = 127
3 3
Q − Q Q − Q
prqFkZd fopyu xq.kkad = 3 1 prqFkZd fopyu xq.kkad = 3 1
Q + Q 1 Q + Q 1
3
3
64 − 58 6 127 − 112 15
= = = .049 = = = .063
64 + 58 122 127 + 112 239
vr% Hkkj esa Å¡pkbZ dh vis{kk vf/d vifdj.k gSA
mnkgj.k (Illustration) 6: fuEu caVu ls vifdj.k osQ prqFkZd xq.kkad dk ifjdyu dhft,μ
in dk osQUnzh; eku% 1 2 3 4 5 6 7 8 9 10
vko`fÙk % 2 9 11 14 20 24 20 16 5 2
gy (Solution): fn;s x;s eè;&fcUnq osQ vk/kj ij oxkZUrj Kkr fd;s tk;saxsA eè; fcUnq dk vUrj 1 gSA
vr% 0.5 eè; ewY; esa ?kVkus o tksM+us ij fupyh o Åijh lhek izkIr gks tk,xhA
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