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bdkbZμ6: vifdj.k% vFkZ ,oa fo'ks"krk,¡] vifdj.k osQ lkis{k ,oa fujis{k eki] jsat] prqFkZd fopyu ,oa 'kred foLrkj
tkrk gSA uksV
vifdj.k dh ;g jhfr foLrkj ,oa vUrj&prqFkZd foLrkj ls Js"B ekuh tkrh gS D;ksafdμ(1) ;g pje ewY;ksa
ls izHkkfor ugha gksrhA (2) ;g Js.kh osQ eè; osQ 80% ewY;ksa ij vk/kfjr gksrh gSA 'kred foLrkj leadekyk
osQ foHkktu ewY;ksa ij vk/kfjr gksrs gSaA budk iz;ksx ;g fuf'pr djus osQ fy, fd;k tkrk gS fd Js.kh osQ
80% ewY; fdu lhekvksa osQ vUrxZr iSQys gq, gSaA
'kred foLrkj esa ogh xq.k&nks"k gksrs gSa tks foLrkj o vUrj&prqFkZd foLrkj esa ik;s tkrs gSaA f'k{kk o euksfoKku
osQ {ks=k esa ;g jhfr mi;ksxh gSA
mnkgj.k (Illustration) 4: 100 fo/k£Fkvksa dks fdlh ijh{kk esa fuEu vad izkIr gq, gSaμ
izkIrkad Nk=kksa dh la[;k izkIrkad Nk=kksa dh la[;k
46—50 2 21—25 30
41—45 5 16—20 20 (1) eè;orhZ 50% Nk=kksa o
36—40 5 11—15 15
(2) eè;orhZ 80% Nk=kksa osQ
31—35 6 6—10 5 izkIrkdksa dk foLrkj Kkr
26—30 10 1—5 2 dhft,A
gy (Solution): fuEu Js.kh dks vkjksgh Øe esa foU;kflr djosQ lap;h vko`fÙk fudkyh tk,xhμ
vad vko`fÙk lap;h vko`fÙk vad vko`fÙk lap;h vko`fÙk
1—5 2 2 26—30 10 82
6—10 5 7 31—35 6 88
11—15 15 22 36—40 5 93
16—20 20 42 41—45 5 98
21—25 30 72 46—50 2 100
N = 100
izFke prqFkZd r`rh; prqFkZd
N 3N
Q = Size of th item Q = Size of th item
1 4 3 4
100 300
= Size of or 25 item = Size of or 75 item
th
th
4 4
∴ 16 – 20 is the Q class ∴ (26 – 30) is the Q class
1 3
i i
Q = l + (q – C) Q = l + (q – C)
1 f 1 3 f 3
5 5
= 15.5 + (25 – 22) = 25.5 + (75 – 72)
20 10
5 × 3 5 × 3
= 15.5 + = 25.5 +
20 10
= 15.50 + .75 = 25.5 + 1.5
Q = 16.25 Q = 27.0
1 3
10ok¡ 'kred 90ok¡ 'kred
10N 90N
P = Size of th item P = Size of th item
10 100 90 100
= Size of 10 item = Size of 90 item
th
th
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